AP chemistry specific heat problem?
a coffee cup calorimeter contains 50 g of water at 60.51 degrees celcius. a 12.4g piece of graphite at 24.21 degrees celcius is placed in the calorimeter. the final temperature of the water and the carbon is 59.02 degrees celcius. calculate the specific heat of carbon. the specific heat of water is 4.18 j/g*C
thank you
59.02C – 24.21C = 34.81degC temperature change for graphite
60.51C – 59.02C = 1.49degC temperature change for water
(50gH2O)(1.49degC)(4.18J/gH2O) = 311.41 J heat lost by water and gained by graphite (G)
(311.41J)/(12.4gG)(34.81degC) = 0.7214 J/g-degC
Specific Heat Capacity Sample Problem 1
