Tag Archives: thermodynamics

Specific Heat Problems Chemistry

specific heat problems chemistry
AP chemistry specific heat problem?

a coffee cup calorimeter contains 50 g of water at 60.51 degrees celcius. a 12.4g piece of graphite at 24.21 degrees celcius is placed in the calorimeter. the final temperature of the water and the carbon is 59.02 degrees celcius. calculate the specific heat of carbon. the specific heat of water is 4.18 j/g*C

thank you

59.02C – 24.21C = 34.81degC temperature change for graphite

60.51C – 59.02C = 1.49degC temperature change for water

(50gH2O)(1.49degC)(4.18J/gH2O) = 311.41 J heat lost by water and gained by graphite (G)

(311.41J)/(12.4gG)(34.81degC) = 0.7214 J/g-degC

Specific Heat Capacity Sample Problem 1

Chemistry Specific Heat Problems

chemistry specific heat problems
chemistry specific heat?

im going over some chemistry problems before school starts back, but i dont understand this specific heat problem…need help.

a sample of metal with a mass 250g is heated to 130 degrees C and dropped into 425g of water at 26 degrees C. The final temperature of the water is 38.4 degress C. What is the specific heat capacity of the metal if 1.2 x 10 ^3 J are lost to the environment?

PLEASE AND THANK YOU!

q (water) = 425 g x 4.18J x ( 38.4 – 26) = 2.20 x 10^4 J
2.20 x 10^4 – 1.2 x10^3 = 2.08 x 10^4
q ( metal ) = – 2.08 x 10^4 J
q ( metal) = 250 g x specific heat x ( 38.4- 130 ) =
– 2.08 x 10^4
specific heat = 0.908 J / g °C

Specific Heat

Specific Heat Problems

specific heat problems
Help please! Specific problems of the heat?

No idea what I do. Please help! 1) A sample of aluminum absorbs 300.0 J energy. The mass of the sample was 424 g. What was the change in temperature? CP = 0.899 aluminum

Q = mass x specific heat x delta T = 0.899 x 300 424 x delta T delta T = 0.787 ° C

Specific Heat Word Problem